Explanation dy dx = 2x (y x2y)2 this is separable dy dx = 1 y2 ⋅ 2x (1 x2)2 y2 dy dx = 2x (1 x2)2 ⇒ y3 3 = − 1 1 x2 C
Y(xy+2x^2y^2)dx+x(xy-x^2y^2)dy=0- Solve ( y 2 2 x 2 y) d x ( 2 x 3 − x y) d y = 0 I tried to solve the differential equation in the following manner, but I am unable to arrive at the correct solution The correct solution is 4 ( x y) 1 3 − 2 3 ( x / y) 3 2 = C Please help me identify my mistake in the solution RECTIFICATIONSolve ( x 2 y − 2 x y 2) d x − ( x 3 − 3 x 2 y) d y = 0 written 42 years ago by teamques10 ★ 17k • modified 24 months ago engineering mathematics
Y(xy+2x^2y^2)dx+x(xy-x^2y^2)dy=0のギャラリー
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